Bash Scipt combines one or more chronologically ordered log files into a single sorted output file, removing all the rows that contain data older than 24 hours from the current system datetime

The required hours of data can be achieved by replacing 24 below with desired hours. Here I am sorting with first 2 columns because that's how my logs are stored say:

2018–08–25 20:24:49 webserver-1:production | Cache warmed
2018–12–30 1:15:01 webserver-2:producction | Server started

cat /dev/null>>result.txt
cat $@ | sort --key=1,2 > tmp.txt
sed -i ‘s/\\n/\n/g’ tmp.txt
awk -v d="$(date -d'24 hours ago' +'%F %T,0000')" '$1" "$2>=d' tmp.txt | tee result.txt
if [ -s result.txt ]
then
echo “non_blank file”
else
echo “” > result.txt
fi